# Line slope calculator 6x+y=28

**Straight line given by points A[3; 10] and B[4; 4]**

## Calculation:

**Slope-intercept form of line:**y = -6x+28

**Canonical form of the line equation:**6x+y-28 = 0

**Parametric form of the line equation:**

x = t+3

y = -6t+10 ; t ∈ R

**Slope:**m = -6

**Slope angle of line: φ =**-80°32'16″ = -1.4056 rad

**X intercept:**x

_{0}= 4.6667

**Y intercept:**y

_{0}= q = 28

**Distance line from the origin:**d

_{0}= 4.6032

**The length of the segment AB: |AB| =**6.0828

**Vector: AB =**(1; -6)

**Normal vector: n =**(6; 1)

**Midpoint of the segment AB: M =**[3.5; 7]

**Perpendicular Bisector equation:**x-6y+38.5 = 0

**Vector OA = (3; 10) ; |OA| = 10.4403**

**Vector OB = (4; 4) ; |OB| = 5.6569**

**Scalar product OA .OB = 52**

**Angle ∠ AOB = 28°18'3″ = 0.4939 rad**