# Line slope calculator 5x+4y=32

**Straight line given by points A[0; 8] and B[4; 3]**

## Calculation:

**Slope-intercept form of line:**y = -1.25x+8

**Canonical form of the line equation:**5x+4y-32 = 0

**Parametric form of the line equation:**

x = 4t

y = -5t+8 ; t ∈ R

**Slope:**m = -1.25

**Slope angle of line: φ =**-51°20'25″ = -0.8961 rad

**X intercept:**x

_{0}= 6.4

**Y intercept:**y

_{0}= q = 8

**Distance line from the origin:**d

_{0}= 4.9976

**The length of the segment AB: |AB| =**6.4031

**Vector: AB =**(4; -5)

**Normal vector: n =**(5; 4)

**Midpoint of the segment AB: M =**[2; 5.5]

**Perpendicular Bisector equation:**4x-5y+19.5 = 0

**Vector OA = (0; 8) ; |OA| = 8**

**Vector OB = (4; 3) ; |OB| = 5**

**Scalar product OA .OB = 24**

**Angle ∠ AOB = 53°7'48″ = 0.9273 rad**